Class 8 maths chapter 3 exercise 3.2

In this page we have NCERT Solutions for Class 8 Maths Chapter 3 Exercise 3.2.This exercise has questions about Sum of the Measures of the Exterior Angles of a Polygon, how to find the xterior angles given inetrior angles. Hope you like them and do not forget to like , social share and comment at the end of the page. NCERT Solutions for Class 8 Maths Chapter 3 Exercise 3.2 Question 1 Find x in the following figures a. b. Answer We know that the sum of all exterior angles of any polygon is 360º. a. 125° + 125° +x= 360° 250° +x= 360° x= 110° b. 60° + 90° + 70° +x+ 90° = 360° 310° +x= 360° x= 50° Question 2 Find the measure of each exterior angle of a regular polygon of (i) 9 sides (ii) 15 sides Answer (i) Sum of all exterior angles of the given polygon = 360º Each exterior angle of a regular polygon has the same measure. Advertisements =360/9= 40° (ii) Sum of all exterior angles of the given polygon = 360º Each exterior angle of a regular polygon has the same measure. Thus, measure of each exterior angle of a regular polygon of 15 sides =360/15=24° Question 3 How many sides does a regular polygon have if the measure of an exterior angle is 24°? Answer Sum of all exterior angles of the given polygon = 360º Measure of each exterior angle = 24º Advertisements =360/24= 15 Question 4 How many sides does a regular polygon have if each of its interior angles is 165°? Answer -Measure of each interior angle = 165° Measure of each exterior angle = 180° − 165° = 15° The sum of all exte...